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Capure in front or behind?


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If I do a fly by the Mun, and behind behind the mun's direction of orbit, then I get a gravity assist increasing my orbit of Kerbin(not sure on correct terminology here, orbital energy?).  If I pass in front, then my Kerbin orbit is decreased.  So if I were wanting to save some dV on deorbiting to Kerbin, then first doing a fly by of the Mun on the front side is a good way to lose some orbital energy.

However, I'm wondering if this matters within the reference frame of the Mun, if my goal is to capture and orbit the Mun, will it save me dV to put my periapsis on the front side of the Mun?  I would imagine if my periapsis is on the backside of the Mun(relative to it's orbital direction) then I spend more time approaching and thus spend more time accelerating and thus will need to expend more dV to slow down to capture.

My fairly non scientific testing with nodes indicates this probably is the case, saving roughly 10% dV in the couple cases I tried.  Basically using a radial node at the midpoint of my Kerbin orbit to set my approach up to the Mun to pass in front or behind at the same Mun periapsis height, then using a retrograde node at the Mun periapsis to compare dV needed to drop apoapsis to 100km.

Edited by AaronLS
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It's a bit more complicated than that. Whether you get a return to the parent SOI faster or slower than you entered it is mostly to do with what angle relative to the assisting bodies orbit you enter at and what angle you leave at. A while ago I wrote up some conclusions 

 

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4 hours ago, tomf said:

It's a bit more complicated than that. Whether you get a return to the parent SOI faster or slower than you entered it is mostly to do with what angle relative to the assisting bodies orbit you enter at and what angle you leave at. A while ago I wrote up some conclusions 

 

That's a handy write-up!

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Yup, this is about in-game stuff, not the real world.  Moving.

(FYI, if you see a thread that looks like it needs moving or any other sort of maintenance requiring moderator attention, the best way to do that is to report the post, rather than just saying "this needs moving" or whatever.  The former actually gets our attention.  The latter doesn't-- nothing will happen unless you get lucky and one of us just happens to see the comment.)

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The question wasn't meant to be about the Kerbal solar system.  I gave that as an example only.  It was meant as a question about physics.

The linked article seems to deal with the affect a fly-by has on the orbit around the parent body, which is not what I'm asking about.

Anyhow, not a big deal.

 

Edited by AaronLS
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Apollo 11 used to go with the "in front" approach as you can see here 

fin-apolloroute-xa.jpg

 

as you figured out it takes a tiny bit more energy than the "behind approach". However IIRC they chose this path in case of a malfunction in the engine when at the LOI point. if you go with the behind approach and your engine fails, you will come back to earth with more energy and therefore a higher orbit which in case of a total engine loss cause you to be stuck in space forever... or at leat an awful amount of time if you rely on orbit decay to get you back down. 

In the same situation the "in front" approach will get you back to earth with a lower orbit, which naturally bring you down on earth in case of a mishap. 

So for the sake of it I tend to use the same path as Apollo missions, especially if I want to be greedy and save the maximum fuel possible for a flyby mission

 

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My general impressions are as such:

Translunar (in front of the Mun) costs slightly more on injection (initial burn from LKO), and a bit more on landing and ascent due to the retrograde orbit you end up in.

However, translunar is preferred for flybys and missions where you want a return-to-Kerbin abort mode. A free-return trajectory is a special case of translunar injection where, if you don't maneuver, you end up just crossing back into Kerbin atmosphere for reentry. This was what was used by the Apollo missions, since if the service module engine failed to fire properly, they would simply just return to Earth. It's also widely used for flybys, as then it's very cheap to get your flyby mission back to Kerbin for recovery.

In my experience, it's hard to exactly nail a free-return trajectory (particularly if you want a low perilune), but even if you don't exactly nail it, you can at least get something close, where only a small adjustment (possibly with RCS or the lander engine) will correct you to a proper reentry profile. In general, though, you want to at least get something close, which means burning earlier than normal, and with a bit more delta-V than normal.

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If you want a neat trick (but you probably won't bother to do it twice), it's possible to get a free return trajectory that captures to a prograde orbit.  The catch is that it takes more delta-v and a longer time, since you pass Kerbin apoapsis, loop around Mun and get ejected (assuming no burn) heading back towards Kerbin apoapsis.

I do wonder how LOS is now with capturing to a low retrograde orbit...

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It is as tomf said: If you leave with an angle more prograde relative the assisting body than you entered, then you will gain prograde velocity during the encounter. If you leave less prograde than you entered, then you will lose it.

 Energy gain and loss is all about the angles.

HTHs,

-Slashy

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On 12/20/2016 at 3:57 AM, psychopoak said:

Apollo 11 used to go with the "in front" approach

as you figured out it takes a tiny bit more energy than the "behind approach". However IIRC they chose this path in case of a malfunction in the engine when at the LOI point.

Yeah, they used a "free return trajectory" where if the engines failed altogether, the craft would end up going around the Moon and coming back to Earth more or less exactly on the correct path for reentry.  This ended up being very useful on Apollo 13.

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