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About MAFman

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    Rocketry Enthusiast

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    Robotics, programming, computer engineering, chemistry

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  1. How do I make the propellers work underwater? Why don't they generate lift underwater at the cost of causing drag that reduces the motor speed?
  2. How do you use the turboprop engine for single-engine planes? When I’ve tried, it makes the plane roll in the opposite direction because of the torque, and it doesn’t get the plane going fast enough to take off.
  3. Why do the Breaking Ground motors not have sound effects? I feel that's something that's missing from the game. How would I go about adding that via a mod?
  4. What would it take to do a "real"-ish BepiColombo mission, using the actual sequence of flybys? Would it save delta-v at the cost of a huge amount of time?
  5. So it is just for fun, not intended to be anywhere realistic. Basically, if you want realism that's what mods are for?
  6. So if that's the case, it's just game magic? Or, the game could be using hydrogen peroxide as monoprop, which can be produced from water, I think...
  7. So 16 kg of methane would be just over three units of liquidFuel, and 64 kg of O2 would be just under 13 units of oxidizer. In order to make the 0.9 to 1.1 ratio of liquidFuel to oxidizer, I'd need 15 * 1.1 = 16.5 kg of oxidizer, wasting one kg of methane and 47.5 kg of oxygen. So for 100 kg of ore, which is 10 units, and assuming the water just comes from magic (?) or something, I could make 3 units of usable LF and 3.3 units of usable oxidizer. Is this correct-ish?
  8. Yes, just replace the WheelSounds.dll you have with the new one.
  9. I turned the molar equations into mass equations, rounding to the nearest gram: 100g CaCO3 -> 56g CaO + 44g CO2 72g H2O -> 8g H2 + 64g O2 44g CO2 + 8g H2 -> 16g CH4 + 36g H2O Useful products: 16g CH4, 64g O2 Waste: 56g CaO, 36g H2O Can someone help me convert this into "units" of Ore, LiquidFuel, and Oxidizer?
  10. Specifically, here's the reaction details. Fuel and Oxygen Production CaCO3 + 178 kJ -> CaO + CO2 4H2O + 948.96 kJ -> 4H2 + 2O2 CO2 + 4H2 + 165 kJ -> CH4 + 2H2O 2H2O + 474.48 kJ -> 2H2 + O2 Overall Reaction: CaCO3 + 4H2O + 1766 kJ -> CaO + CH4 + 3O2 + 2H2 Methane Combustion CH4 + 2O2 -> CO2 + 2H2O + 891 kJ Products that could be used for electricity: 2H2 + O2 -> 2H2O + 474.48 kJ This only took about an hour to figure out, LOL
  11. I think I can do that, since I have a whole bunch of time on my hands.
  12. I was looking around for how generic ore could be turned into generic liquid fuel an oxidizer, and I think I found a candidate. Perhaps the ore that you mine is actually methane clathrate (www.wikipedia.org/wiki/Methane_clathrate) trapped in the dirt, but I’m not sure how the methane is extracted. Or (and I like this better), the ore is a carbonate mineral from which CO2 and hydrogen are liberated through heat, and then converted into methane by the Sabatier reaction, and the resulting water is electrolyzed to make liquid oxygen. The issue is, how is this process reflected in the inp
  13. I found that the tilde key ~ resets the focus on the active vessel.
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