jonpfl Posted May 15, 2017 Share Posted May 15, 2017 All, What does it mean to test something on an escape trajectory out of Kerbin? I just assumed is have a flight destined for over 70k and then activate engine. i flew out beyond 70k and contract never lit up! Thx jonpfl Link to comment Share on other sites More sharing options...
AHeroReborn Posted May 15, 2017 Share Posted May 15, 2017 An escape trajectory means it will leave Kerbins SOI (gravitational field). It means you must create an orbit that would land you in orbit around the sun. It may also count if you use a trajectory that will give you a quick flyby of the mun or minmus. Link to comment Share on other sites More sharing options...
Starman4308 Posted May 15, 2017 Share Posted May 15, 2017 As a small aside: while the delta-V difference is really not that large, you could in theory save a sliver of delta-V going to Kerbin escape by slingshotting around the Mun. For that, you would want a very basic cislunar transfer* to the Mun, except you just don't brake into Mun orbit, and keep on going to escape Kerbin SOI. *Translation: your trajectory has you get captured in front of the Mun, you pass behind it, and get slingshotted back out in front of the Mun. Link to comment Share on other sites More sharing options...
Shadow Wolf56 Posted May 16, 2017 Share Posted May 16, 2017 It's cause Kerbins soi is round about 85 million kms out. (so if you didn't have a contract light up it's because you never leaved kerbin orbit...) Link to comment Share on other sites More sharing options...
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