The Equatorial Minmus Challenge

[Superfluous J]

1 hour ago, Pand5461 said:

Peace of cake.

You massacred that cake!

[Pand5461]

15 hours ago, OHara said:

Reach Minmus at its northernmost or southernmost points in its orbit, 90° from either nodal point. 

I've now realized, this is essentially what my optimization arrived to.

9 hours ago, 5thHorseman said:

You massacred that cake!

Aaah! Correct use of homophones isn't my strong point, especially after too little sleep and too much coding.

On the challenge topic, I'm getting more familiar with kRPC, so probaly I'll be able to continuously tweak departure burn for arriving to Minmus as equatorially as possible. And even do stuff with a proper launch, not Alt+F12-ing ship to orbit.

[The Flying Kerbal]

Sorry for not reading this earlier, I've been a bit busy lately and KSP has had to be put on the back burner for a few days.  So my little question in another thread resulted in a challenge eh?  I think I'll have to have a go at this, probably failing spectacularly in the process.

[MarvinKitFox]

Minmus burn must be pure retrograde? and AT perigee?

Owch!

Actually, I'm claiming Heisenberg, and stating that allowing a burn only *at* perigee must be of zero duration, thus some higher order of infinite acceleration.

Edited April 22, 2018 by MarvinKitFox

[Superfluous J]

On 4/22/2018 at 5:34 AM, MarvinKitFox said:

Minmus burn must be pure retrograde? and AT perigee?

I see what you did there. But while we're being pedantic, you can't burn at Minmus perigee at all. It'd be like burning at 27:00 am on Thendsday Febtober Sevth.

The Minmus burn must be centered on periapsis within a reasonable deviation.