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You have 10,000 of whatever is in your profile picture. What do you do?


Ultimate Steve

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18 hours ago, Ultimate Steve said:

If you have an arm in your profile picture you can afford to lose a lot of arms. But if they are only left arms then you'll just have two left hands for the rest of your life unless you can manage to not lose the original right one.

Well I am left-handed so that's not so bad.

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I have 20000 model rockets (Cuz I have 2 in my profile pic)

10000 emperor penguins

10000 emperor penguin chicks

10000 SSTOs.

 

The emperor penguins get in the SSTOS while each penguin chick uses 2 model rockets to lift itself. 

Boom. 20000 penguins IN SPACE!!!!!

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1 hour ago, TeslaPenguin1 said:

I have 20000 model rockets (Cuz I have 2 in my profile pic)

10000 emperor penguins

10000 emperor penguin chicks

10000 SSTOs.

 

The emperor penguins get in the SSTOS while each penguin chick uses 2 model rockets to lift itself. 

Boom. 20000 penguins IN SPACE!!!!!

Did you just change your profile picture for this thread?

*changes profile picture to 1 million dollars*

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10,000 Kerbals on EVA.

I'll build a space elevator out of them, all the way up to....wait.....maths time...

Kerbals are approximately 1 metre tall. If I stack them up into a tower, they'll reach 10,000 metres, which is the cruising altitude of most commercial airliners.

Dammit.

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On 8/2/2018 at 3:33 PM, Earthlinger said:

An army of Canadaballs

.....Which is relatively useless, unless they can move and are able to be commanded

*munches on popcorn*

Ha, nice emphasis. Love the

On 8/2/2018 at 3:33 PM, Earthlinger said:

*munches on popcorn*

part

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Saturn itself is roughly 95 times the mass of earth. That would be 95M* 10000 = 950000M

Divide that by the number of earth masses that are in sol.

950000M/333000M = 2.853M

If my math is correct (which it might not be because I've been awake since 3 am.) You would have a star 2.853 times the mass of the Sun. It would be an A-type main sequence star, with a luminosity of 111L☉.

Note that this does include the moons, rings and other particles.

 

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1 hour ago, Adstriduum said:

Saturn itself is roughly 95 times the mass of earth. That would be 95M* 10000 = 950000M

Divide that by the number of earth masses that are in sol.

950000M/333000M = 2.853M

If my math is correct (which it might not be because I've been awake since 3 am.) You would have a star 2.853 times the mass of the Sun. It would be an A-type main sequence star, with a luminosity of 111L☉.

Note that this does include the moons, rings and other particles.

 

I do agree, Earth needs another moon or two... or 620000.

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24 minutes ago, Earthlinger said:

Is it just me who understood the mole concept and the surrounding details/formulae perfectly well on the first day but somehow struggles with basic math?

It's like I'm selectively dumb :D

Not just you, the calculations themselves are pretty easy, they're just basic division, its the understanding of the mole that is complex.

Also I have 10,000 US Flags, 10,000 Neil Armstrong's and 10,000 moon lander legs. Does anyone wish to buy any astronaut? A real life astronaut?

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On ‎9‎/‎17‎/‎2018 at 12:33 PM, adamgerd said:

Not just you, the calculations themselves are pretty easy, they're just basic division, its the understanding of the mole that is complex.

Also I have 10,000 US Flags, 10,000 Neil Armstrong's and 10,000 moon lander legs. Does anyone wish to buy any astronaut? A real life astronaut?

And 10,000 moons

Or bits of moons.

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