Write a number and then an equation to do to it, get out your calculators!!!

[Ryaja]

The number starts at 0 the variable A will be used.

Use scientific notation for numbers larger that 10 digits(or smaller) and for irrational numbers after 10 digits down write three dots.

If you get pi copy the symbol from here: π

you choose what equation to do to A.

Wait 2 minutes and another person's post after each post to post again.

If someone's post is invalid tell them as soon as possible so the number is correct.

You might need this: https://www.desmos.com/scientific

Here is an example:

Poster 1: A = 0, A+1

Poster 2: A=1, A*10+5

Poster 3: A=15, A*78+5^6

and so on.

I will start

A=0

A+(10^2)

Edited May 26, 2022 by Ryaja
Clarification

[PlasmaIndustries]

A=100
(A*5)-7

[Ryaja]

A=493

A^A

Edited May 24, 2022 by Ryaja

[CFYL]

What... Oh @Ryaja how do you expect people to do this

A= 37456845848174934149503672646357576275294359248898047992368358678264449767885418086161848869131100935421561608889687071867916246355767443525297117895059185007028389239539359607988406665757396379283168512410166408741900118309992008127564135215014196285465515059262833734169186763350694323890102923122134823610205512968018283798422918225969409305114133189147264982513712371605528950638824115962539607299536039304015514340555186203247412588365087874865414799221108239186192563197895178750178968795479601437736585845601253478277332032335757526350639017945952091968988824933603638538633812519957828699106909041151580111667624438497656472138587193967853579263190508255369457346153316873372155224964151987619126855945927870815638648228535648088847375458875881126529177122161658185822364856152678113191392362124582559261951948993703474275475985520842122182482321780481893296599964095611116989153818871221405169791910227816866746763124153122960799088413911861157558534951523095393786921735806680431156256419100808988827538099116339163897251334571608477389408741398944528899824942061728460798443146970084748707980244534047515980943526891198328375070351822173875541537298344668945020620823931260373813736975592513392516369474800008938326462410016558310676149618307451779292055912744574367401711055284331745408068587915526845766107697520093

Now the credit goes to https://www.wolframalpha.com/input?i2d=true&i=Power[493%2C493]

So my equation is

A-A (A minus A)

to make this "human-calculate-able" again...

[Ryaja]

@CFYL Use scientific notation and a calculator.

 

A=0

A-100^-5

[Nazalassa]

A =                  -1                  
          10 000 000 000

A+1.000 000 000 01

[Ryaja]

A=1

A+π*π

Edited May 26, 2022 by Ryaja

[Dr. Kerbal]

((2(√69 + 852^-6523 - 0.2866) ÷ 42546955 - 0.45905031276) + 0.08189937448 - (-0.37741713735) ≈ 1

A very long equation to get to one. Phew, I hope it is true though.*
*The approximate sign is there as square roots of numbers that are not perfect squares can turn out to be irrational numbers. Hence the answer is approximate as the difference between the real answer (or with done with a calculator that calculated more of the square root true value).  However, the difference between the real answer and one is so insignificant and small (very small difference) that you can round up to one.

Or you could use this.



This apparently equals one.

Edited May 26, 2022 by Dr. Kerbal
Gave explanation for the approx. (≈) symbol.

[CFYL]

I think the OP wants us to calculate the equation that the last player has given. Your approximation is amazing though.

When it comes to irrational numbers, I somehow think approximation is needed. So @Ryaja, could you set up some rules that define how many significant numbers we need to include in our values? π is an accurate number, but we can't write all its digits. Will 3.14 be good enough? Or do we need 3.14159265? Or even π = 3.14159 26535 89793 23846 26433 83279 50288 41971 69399 37510 58209 74944 59230 78164 06286 20899 86280 34825 34211 70679?  A calculator will make this play-able, but we need to know how accurate we must be.

So A could now be 37.46 or 37.46216. There are a infinitely more digits after these.

Spoiler

Or do we need the Physics way of analyzing uncertainty? That could be hard.

Please add rules regarding accuracy. It could be just me, but I think it isn't.

[Ryaja]

@CFYLDone! I also have a link to a calculator to use.

[Ryaja]

17 hours ago, Dr. Kerbal said:

((2(√69 + 852^-6523 - 0.2866) ÷ 42546955 - 0.45905031276) + 0.08189937448 - (-0.37741713735) ≈ 1

A very long equation to get to one. Phew, I hope it is true though.*
*The approximate sign is there as square roots of numbers that are not perfect squares can turn out to be irrational numbers. Hence the answer is approximate as the difference between the real answer (or with done with a calculator that calculated more of the square root true value).  However, the difference between the real answer and one is so insignificant and small (very small difference) that you can round up to one.

Or you could use this.



This apparently equals one.

Edited 17 hours ago by Dr. Kerbal
Gave explanation for the approx. (≈) symbol.

So where is A?

[Nazalassa]

First letter to appear

[Ryaja]

46 minutes ago, Nazalassa said:

First letter to appear

No, the variable A

[Nazalassa]

Yup, A is [equal to] a very long equation for one.

[Ryaja]

A=1 I guess

A*2^100

[Nazalassa]

A = 3.7778932e+22

A-2^99

[CFYL]

1*2^100, I get 1.267650600e+30. 

2^75 and I get 3.777893186e+22.

So I'll take 2^100 - 2^99, which is  A = 6.338253001e+29.

ln[ln(A)]

Edited May 30, 2022 by CFYL

[Nazalassa]

A = 4.22860692955

A/ln(ln(A))