kerbo_noob

Hi, I just wanted to match the theoretical result from the equation with actual result in KSP . I just want to get my basics straight as I am a newbie. Once I get the basics, I will try to design crafts myself to orbit Kerbin and then on to Mun and beyond! I really love this game.

Thank you all for the replies!! My main aim was to understand the equation of burnout velocity by matching the theoretical result with what I observe in KSP (I know it is crazy ). Thanks for pointing out that the atmosphere is reason I got a different result in KSP. I can sleep peacefully now because I thought I messed up the calculations (or the equation) and it was bothering me all along. I want to try the test without atmosphere. Is there a way to turn atmosphere off in KSP? Once again, thank you all for the replies!

I am trying to learn the basics of rocket science using a single stage rocket in KSP. Using the rocket equation I calculated the burnout velocity of my single stage rocket to be around 2327 m/s. Vbo=Isp*9.8*ln(Total Mass/Dry Mass) - g*burn time The rocket has a Mk1 Command Pod (mass=0.84), a Mk16 Parachute(mass=0.1) and an RT-10 solid Fuel Booster(mass=3.7475 and fuel mass=3.25, Isp=225). If I launch the rocket vertically upwards the fuel burns for about 29s (theoretical value is 28.7) but the maximum speed shown on the navball at the end of the burn is around 720 m/s. I am not sure if I missed something while calculating the burnout velocity. Is the speed shown in the navball at the end of burn called burn out velocity? If so why such a huge difference between the speed shown in game and the theoretical value? Could someone please let me know if I missed something?