Just for anyone who is interested, I figured out how to get around this problem. Here is a picture of the orbits to hopefully explain better: The main problem was coming from assuming we would transfer to Vall using the dashed cyan orbit. The speed leaving the SOI would have to be smaller than physically possible so calculators might show a negative burn. Anyway, the way to get around it is: 1. Solve for the slowest speed you could leave the SOI from your orbit 2. If the speed you would need to go is slower than this minimum speed, then solve for the flight-path angle (or zenith angle, whichever you prefer, see http://www.braeunig.us/space/orbmech.htm) required so that leaving at the minimum speed and that angle, you will have your desired apoapsis (or periapsis if going toward a target lower). This involves solving a quadratic function for cos(theta) (or sin(theta) using zenith angle). 3. From the known flight-path angle and speed just before leaving the SOI, you can calculate the speed and flight-path angle after leaving by adding the velocity vectors. 4. Given the altitude, speed and flight-path angle just outside the SOI, you know your new trajectory (blue solid orbit) 5. The delta-V in this case is simply the delta-V required to lift your apoapsis to the SOI. From there, you are moving at the minimum allowable speed and if the point of exit is correct, you will exit with the right speed and direction to make it to your target at apoapsis (or periapsis if going lower) I won't go into the mathy details but this would at least give you an idea of how to do it. I may end up doing a small article on this once I have a definitive answer of where to put a space station in Jool orbit to minimize future trips' delta-V.