Brand new to the forums, all because of this The ISS orbits Earth at a periapsis of 330km, and apoapsis 435km (According to Wikipedia). To get the same 'distance to the horizon' from a satellite orbiting Kerbin, (Using the formula d = √(2Rh + h^2)) you need heights at 157.9km, and 169.5Km respectively. But this would not give the same look. If you were to scale the distance to the horizon to match the scale of Kerbin (One tenth of the distance to the horizon? As in 2077/10 and 2394/10), it would then give the same look as the ISS does. This would be at 50.0km periapsis and 53.6km apoapsis, but this wouldn't work because of atmosphere. I'm not 100% sure if this is correct, so, here are my workings, check them please! Radius of the Earth is around 6371km, Kerbin is 600Km. ISS: √(2*6371*330 + 330^2) = 2077km (To the horizon, at periapsis). √(2*6371*435 + 435^2) = 2394km (To the horizon, at apoapsis). Kerbin ISS: √(2*600*X + X^2) = 2077km √(2*600*Y + Y^2) = 2394km Rearrange the equation.. √(2*600*2077) = X √(2*600*2394) = Y X = 157.9km Y = 169.5Km Kerbin ISS relative distance to the horizon: √(2*600*X + X^2) = 2077km √(2*600*Y + Y^2) = 2394km (Divide answer by 10) Rearrange the equation.. √(2*600*208) = X √(2*600*239) = Y X = 50.0km Y = 53.6km