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Boring chemistry problem


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I can balance equations but only if I already know both sides. Trying to find the following products:

Na2S2O5 + O2 = ?

Na2S2O5 + KNO3 = ?

Na2S2O5 + KNO3 + Fe2O3 = ?

Na2S2O5 + KNO3 + C12H22O11 = ?

KNO3 + C12H22O11 = ?

KNO3 + C12H22O11 + Fe2O3 = ?

Thanks!

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Looks like a homework problem because it's a very specific question, but it isn't actually homework. I graduated college a long time ago. 

Trying to estimate specific impulse of different solid fuels, but I can't get specific impulse without specific energy, and I can't get specific energy unless I know the equation products so I can balance it and calculate bond energies.

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Na2S2O5 + O----> Na2S04 + S03

Na2S2O5 + KNO ----> Na2S04 + KNO + S0 ----> Na2S04 + 1/2K2S04 + 1/2N2

Na2S2O5 + 2KNO ----> 2KNaS04 + N2O3 

Na2S2O5 + KNO + C12H22O11 =

12C - 12CO2 Need 24O

22H - 11 H20   Need 11O

11O

The net requirment is 240

8 Na2S2O5 + 16 KNO3 + C12H22O11 --------> 16 KNaS0+ 8 N2 +  12 CO2 +  11 H20

Of all the reactions this one looks like it has the best thermodynamics, pretty much driven by the potassium nitrate. The reaction will not go to completion and there will be a ton of nitrous oxide byproducts. There is no way to catalyze the reaction to completion because the sulfur has a poisoning effect.

Edited by PB666
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A couple of those don't look quite right. For the first one, I'm not sure you'd get sulphur trioxide formed preferentially over sulphur dioxide but it's easy to rebalance.

2 Na2S2O5 + 3 O2 = 2 Na2SO4 + 4 SO2

Likewise for the third one, I don't think you'd get N2O3 as a product. My gut feel was that it would probably break down to nitrogen and oxygen and Wikipedia confirms. So...

2 Na2S2O5 +  4 KNO3  ----> 4 KNaS04 +  2 N2 + 3O2

Those are all pretty stable reaction products. Getting oxygen out as a reactant is weird, although you do have a lot of spare oxygen in that system. Maybe you'd get some nitrogen oxides out instead, just not N2O3 :)

For the reactions involving iron oxide, I have no idea what you'd get out. The iron oxide is either going to be inert or acting as a catalyst (hence my uncertainty about reaction products) but you're already at FeIII and potassium nitrate isn't a strong enough oxidiser to move it to FeIV, so the iron oxide isn't going be participating in a net reaction.

 

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9 hours ago, KSK said:

A couple of those don't look quite right. For the first one, I'm not sure you'd get sulphur trioxide formed preferentially over sulphur dioxide but it's easy to rebalance.

2 Na2S2O5 + 3 O2 = 2 Na2SO4 + 4 SO2

Likewise for the third one, I don't think you'd get N2O3 as a product. My gut feel was that it would probably break down to nitrogen and oxygen and Wikipedia confirms. So...

2 Na2S2O5 +  4 KNO3  ----> 4 KNaS04 +  2 N2 + 3O2

Those are all pretty stable reaction products. Getting oxygen out as a reactant is weird, although you do have a lot of spare oxygen in that system. Maybe you'd get some nitrogen oxides out instead, just not N2O3 :)

For the reactions involving iron oxide, I have no idea what you'd get out. The iron oxide is either going to be inert or acting as a catalyst (hence my uncertainty about reaction products) but you're already at FeIII and potassium nitrate isn't a strong enough oxidiser to move it to FeIV, so the iron oxide isn't going be participating in a net reaction.

 

IKR, you would use metabisulfite with chlorine not oxygen. 

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