Absolution Posted July 24, 2012 Share Posted July 24, 2012 @Absolution: I get:Isp1 == (2000*7500) / (62*82.51) ~= 2932.1959 m/sIsp2 == (373*3000) / (14.17*33) ~= 2393.0198 m/s?V1 == 2932.1959 * ln((132.79/(132.79-82.15)) ~= 2826.716 m/s?V2 == 2393.0198 * ln(42.96/(42.96-9.96)) ~= 631.187 m/s? ~= 4129 m/sFor the 3497 m/s, I\'m guessing you did 2392.34*ln(42.96/9.96)?~43 tonnes initial mass; ~33 tonnes of fuel burned; ~10 tonnes final mass. So if I understand the equation correctly '2392.34*ln(42.96/9.96)' would be the correct result for the equation, yes? I think you may have swapped final mass with fuel mass burned (yes, it\'s quite a gas guzzler). Link to comment Share on other sites More sharing options...
UmbralRaptor Posted July 25, 2012 Share Posted July 25, 2012 I\'m confused now:~43 tonnes initial mass; ~33 tonnes of fuel burned; ~10 tonnes final mass.Stage 2:fueled mass = 42.96 tonnesmass of fuel burned = 9.96 tonnesVe of LFE-7E1-A1 engine = 2392.34 m/sdelta-V of the upper stage is 3497 m/sDid it burn ~10 tonnes, or ~33 tonnes? Link to comment Share on other sites More sharing options...
Absolution Posted July 25, 2012 Share Posted July 25, 2012 I\'m confused now:Did it burn ~10 tonnes, or ~33 tonnes?AHA! My mistake. It burns 33 tonnes worth of fuel. I made a typo and I apologize. Link to comment Share on other sites More sharing options...
togfox Posted July 25, 2012 Share Posted July 25, 2012 > ISP (m/s) = Total Thrust / Total mass flow rateFor the life of me I had this understood in my head and now it\'s midnight and I\'ve been thinking about a dozen formula\'s and now I\'m muddled.How does one calculate *TOTAL* mass flow rate for :- two liquid fuel engines the same type and- two liquid fuel engines of different type? Thx. Link to comment Share on other sites More sharing options...
UmbralRaptor Posted July 25, 2012 Share Posted July 25, 2012 Togfox: calculate the mass flow for each engine, and add them up. eg: for 2 of the same type, multiply what you got for one of the engines by 2.For 6 Mk 55s around an Aerospike at sealevel connected to standard (200 u/tonne) tankage:Fuel consumption:Mk 55: (80*200)/(280*9.81) ~= 5.825 u/sAerospike: (250*200)/(390*9.81) ~= 13.069 u/sTotal thrust == 80*6+250 == 790 730 kNTotal mass flow == 5.825*6+13.069 ~= 48.019 u/sOverall Ve == 790*200/48.019 ~= 3290.393 m/s == 335.4 s 730*200/48.019 ~= 3040.490 m/s == 309.9 sAHA! My mistake. It burns 33 tonnes worth of fuel. I made a typo and I apologize.Okay, glad its cleared up.edit: corrected numbers. *glares at the math error* Link to comment Share on other sites More sharing options...
togfox Posted July 26, 2012 Share Posted July 26, 2012 Total thrust == 80*6+250 == 730 kNTiny correction for those that are following the thread. Well explained! Thanks! 8) Link to comment Share on other sites More sharing options...
Chsuae97 Posted July 10, 2013 Share Posted July 10, 2013 You can get you Exhaust Velocity (Ve in equation) by multiplying your ISP (if given in seconds, as it is in the KSP VAB hanger) by the standard gravity, which on kerbin is 9.81. Link to comment Share on other sites More sharing options...
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