The four fours.

[Amram]

93 = (√(!(4)))^4 + 4!! + 4

turns out wolfram-alpha does like !4 instead of needing to input subfactorial(4), just wrap it in parenthesis so its !(4). Forcing the correct order of ops required a few parentheses.

[Chrisd857]

93 = (√(!(4)))^4 + 4!! + 4

turns out wolfram-alpha does like !4 instead of needing to input subfactorial(4), just wrap it in parenthesis so its !(4). Forcing the correct order of ops required a few parentheses.

I've had trouble on !(√4) (it thinks the bang is a NOT symbol)

94 = 4!! * 4!! + 4! + Γ(4)

[Mars90000000]

95=!4*!4 + Γ(4) + 4!!

[Amram]

96 = 4!+4!+4!+4!

yeah, your right it doesn't like !(√4), deciding that the ! is the 'logical not' symbol instead.

[Mars90000000]

97 = 4! * 4 + !4 - 4!!

[Amram]

98 = 4!! * (4!! + 4) + √4

[Mars90000000]

99= !4*!4 + !4 + !4

[Amram]

and

100 = 4!! * (4!! + 4) + 4

Is it just me or have we sped up since Vexx32 last commented?

[Mars90000000]

and

100 = 4!! * (4!! + 4) + 4

Is it just me or have we sped up since Vexx32 last commented?

It appears so! In fact, call him over for our prize!

101 = 4!*4 +!4 - 4

[Amram]

102 = 4!! * (4!! + 4) + Γ(4)

[Mars90000000]

103= ( 4!! + Γ(4) )*4!! - !4

[Amram]

104 = 4!! * (4!! + 4) + 4!!

[Chrisd857]

103 = A( √(!4), 4 ) - 4! + √4

blegh, double ninja'd

105 = A( √(!4), 4 ) - 4! + 4

[Mars90000000]

105 = Γ(4)!! + 4! + 4! + !4

[Amram]

ninja!

lmao

106 = !(Γ(4))*.4 +4-4

[Chrisd857]

106 = A( √(!4), √(!4) ) + Γ(4)!! - √(!4) Edited December 29, 2013 by Chrisd857

[Amram]

the ninja strikes again!

[Chrisd857]

So many ninjas.

107 = A( √(!4), √(!4) ) + Γ(4)!! - √4

[Amram]

indeed

108 = !(Γ(4))*.4 +4/√4

[Chrisd857]

109 = A( √(!4), √(!4) ) + Γ(4)!! * !(√4)

[Amram]

110 = Γ(Γ(4))-!4 +4-4

[Chrisd857]

111 = A( √(!4), √(!4) ) + Γ(4)!! + √4

[Amram]

112 = Γ(Γ(4))-!4 +4/4

[Chrisd857]

113 = A( √(!4), √(!4) ) + Γ(4)!! + 4

[Amram]

114 = Γ(Γ(4))-!4 + !(√4) + √4