Minmus/Inclination

[hempa2]

Im familiar with the Mun and now i wanna go to Minmus. However i dont know how to change my inclination

[Boomerang]

Do your ejection burn to reach Minmus orbit, then set Minmus as your target. You should see two lime-yellow tabs on your orbit. These are the ascending and descending nodes - the points at which it's easiest and most efficient to change your inclination. So set a maneuver node at whichever node comes first, then play around with the normal/anti-normal (up and down) vectors of the node and watch what happens! When you get the inclination change you want, burn at the maneuver node when specified and you'll be good to go.

[Pursuedtank]

You will have to change your inclination at either the ascending node or descending node. Look at this page at the Match Orbital Inclination section. Alternatively you could look at

or this video. The principles put forward for ships is the same for planets/moons.

[skbernard]

you can burn normal or anti-normal at the points where your orbit crosses the 'equator' line of the planet

[EdFred]

There are two ways to do this.

One way (assuming no mods), but it takes more dV is to launch into orbit like you normally would. Go to map view and look at your orbit from the side so the orbit looks like a line. The far side of the orbit, and the near side of the orbit should be in line, and the view of your orbit becomes a line rather than a ellipse or circle. You should be viewing from almost the equator. Using the left or right arrow keys, rotate your view around Kerbin until Minmus' orbit also becomes a line rather than an ellipse or circle. The point where it appears the two orbits cross is where you want to do your burn. Create a node at that point and use the pink triangles (normal/anti-normal) to align your orbit with Minmus' orbit. After you've done this, you go to Minmus just like you would the Mun.

The other way, is go to map view at Kerbin's equator and turn until Minmus' orbit is a line as I described above. Wait until KSC is under that line, and then launch into orbit, but rather than making your gravity turn at 90º, make it at 76º or 104º (I think Minmus' inclination is 14 degrees). You should be pretty well in line with Minmus's orbit, and your inclination should be pretty close.

(I figured I'd get ninja'd)

[Pursuedtank]

The other way, is go to map view at Kerbin's equator and turn until Minmus' orbit is a line as I described above. Wait until KSC is under that line, and then launch into orbit, but rather than making your gravity turn at 90º, make it at 76º or 104º (I think Minmus' inclination is 14 degrees). You should be pretty well in line with Minmus's orbit, and your inclination should be pretty close.

Good advice but the inclination of Minmus is 6º so rather than 76º or 104º, you would want 84º or 96º.

[EdFred]

Good advice but the inclination of Minmus is 6º so rather than 76º or 104º, you would want 84º or 96º.

Thanks, I was going from memory, and I thought it was 14 for some reason.

[Kasuha]

The lazy way: don't match inclinations, approach it along your inclination line instead.

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[Sirrobert]

Set minmus as target

Place manouver node on the now showing 'accending node' or 'decending node'

Adjust inclination with the purple triangles until the node reads 0 (or close to it)

Excecute manouver node

[BudgetHedgehog]

Just throwing it out there - the AN/DN nodes are for the points where the orbits intersect and you'll want to change at those points if you want your final orbit to be at the same inclination around Minmus as Minmus' inclination around Kerbin.

However, it is possible to burn at other times, use less fuel and still get an encounter. I'll post a screenshot in a bit, but Manley did something similar once. Just play with nodes on your way over to Minmus and see the lowest you can get it. For example, if your transfer orbit makes it so the AN/DN are closest to Kerbin, burning at them will be a lot more dV expensive (because you're travelling faster) than burning later on.

[Jesrad]

If you do an inclination correction at the ascending or descending node you'll alter your course by the full amount of angle of inclination (here: 6 degrees):

However, if you do your injection burn at an angle north or south away from ecliptic, you'll need less deltaV because you're then only doing half the inclination correction, or 3°:

I say go with the second method, as demonstrated by Kasuha