Kerbin Dallas Multipass

Animation of the zoom-in

It's... It's so beautiful

Seems the "phone home" signal has passed Saturn's orbit. Can't be long now!

What's the ping?

Yea fair enough. So if you change the variables in this task you magically get different nozzle sizes? Is that where my common sense went astray?

What if I make the nozzle smaller? So I can only get 250l/s through it but the pump still applies 1 MW?

I imagine it is significantly less than 1 MW?

.5 m/s for a 1m² nozzle. That's where my confusion started:)

why not?

Thank you for explaining that. It makes sense. And it answers why both, the flow rate and the power are described in the task. But is it realistic? As I illustrated above, pumping 500l/s through a 1m² pipe will not get us anywhere near a 200m fountain, independent of the power at hand. I think that confused me. If I were to just write down "Since we're pumping water, it depends on the nozzle"... would that be wrong? (I see it's not the desired answer, but isn't that true?)

No. (charlimit makes me post this, too.)

I guess I'm nitpicking here. The question "What height does the water reach" should be "what maximum height can the water reach". If that is the actual question then there is no point in mentioning the 500l/s If I force 500l/s through an infinitely small hole i theoretically get infinite speed. If I don't have infinite power, I obviously can not do that (the power at hand is stated). So what is the 500l/s mention for? is that a distraction?

Thanks for pointing out where in the text i can find it as a reply to my question about why it is mentioned at all. I still don't understand why, seems I suck at physics.

I asked why, not where

Passing .5m³ through a 1m² opening in 1 second gives me a flow speed of .5m/s. The 200m height is not specified in the question, neither is the nozzle size. - - - Updated - - - Yea but why is the 500l/s specified in the question?