Kerbin boat circumnavigation pro tips needed

[HafCoJoe]

Hello I am obviously not new here, BUT I have never done a boat circumnavigation of kerbin before. I know the boat needs to cross land for a number of kilometers as the largest land mass crosses from both poles. I have that down. The question I have is about fuel.

If I am using 2

basic jet engines

and traveling at an average of 90 m/s over water, how much liquid fuel would I need?

That is my most important question.

Here's a less important but still needed answered question:

How many refueling trips would a ship traveling at an average of 114 m/s with 1200 liquid fuel (4 small liquid fuel tanks), and one basic jet engine need?

Please help!

Edited July 14, 2014 by Avera9eJoe

[FleshJeb]

I'll answer the second question first:

The wiki says Basic Jet fuel consumption is 0.1 L/s. I'm assuming that's for sea-level at zero speed. Close enough for our purposes.

1200 L / 0.1 L/s = 12000 s = 3.33 hours.

Kerbin's radius is 600 km, so its circumference is about 3.8 Mm.

3.8 Mm / 114 m/s = 33333 s = 9.26 hours.

You'll need at least two refueling trips.

Using the same math for the first question: 8444 fuel.

[HafCoJoe]

Thank you sooo much! My prototype has 9970 units of fuel in it but moves a bit slower than I mentioned. The math still works though. As for refueling counts on the other, I guessed 3-4 times so I am in good shape there. I'd give you rep twice if I could .

Edited July 14, 2014 by Avera9eJoe

[Alshain]

Keep in mind his calculations were for an equatorial circumnavigation, which is impossible by boat.

[HafCoJoe]

My trip will be a bit longer. Probably 4.0 - 4.2 Mm max. My boat/mega jetski can still do it I think. I can easily redo the calculations too.

[FleshJeb]

Thank you sooo much! My prototype has 9970 units of fuel in it but moves a bit slower than I mentioned. The math still works though. As for refueling counts on the other, I guessed 3-4 times so I am in good shape there. I'd give you rep twice if I could .

You're welcome. Yay, Rep for 5 minutes' work!

Yah, I figured you could extrapolate the math to your specific route and circumstances if you had places to plug in numbers.

Can't wait to see pics of the voyage! It's a task I'd like to try sometime, but I haven't played with boats much.

Expansion of second question:

3.8 Mm / 90 m/s = 42222 s

42222s * 0.2 L /s (two engines) = 8444 Liters

8444 L * 0.005 tons / L (fuel density) = 42.2 tons of fuel.

That's a big boat. :-O

If you're into doing your own math, Dimensional Analysis, otherwise known as unit cancellation is a great tool for checking your logic: http://www.chem.tamu.edu/class/fyp/mathrev/mr-da.html