Looking for a better way to know if the UI is visible or not

[linuxgurugamer]

I need to know whether the UI is being displayed or not. For now, I'm using the following code:

public class UICLASS: MonoBehaviour
{

private bool uiVisible = true;
private static KeyCode toggleUIKeycode = KeyCode.F2;

        public void Update ()
        {


            if (Input.GetKeyDown (toggleUIKeycode))
                uiVisible = !uiVisible;
        }
}

I'm sure there is a better way, since this will not work if there is another mod which issues the following calls:

GameEvents.onHideUI.Fire ();

and

GameEvents.onShowUI.Fire ();

So far, I haven't found it, and was hoping someone could point me in the right direction.

Thanks in advance.

[linuxgurugamer]

This would be my suggestion:

public class UICLASS : MonoBehaviour
{
    private bool uiVisible = true;

    public void Awake ()
    {
        GameEvents.onShowUI.Add(onShowUI);
        GameEvents.onHideUI.Add(onHideUI);
    }

    private void onShowUI ()
    {
        uiVisible = true;
    }

    private void onHideUI ()
    {
        uiVisible = false;
    }

    public void OnDestroy ()
    {
        GameEvents.onShowUI.Remove(onShowUI);
        GameEvents.onHideUI.Remove(onHideUI);
    }
}

This runs when the UI is activated or deactivated, either with F2, another key or by code.

Cheers!

Thanks.

I decided to keep this as a separate class to make it cleaner, so I had to add two functions to get and set the flag:

        public bool isVisible()
        {
            return uiVisible;
        }
        public void setVisible(bool 
        {
            uiVisible = b;
        }

I had to add two functions, since my original code was copied from the main class of my mod.

One thing though, the Awake function isn't being called, I have to call it myself from inside the main Awake function.

Do I need to put something in front of this:

	public class UICLASS: MonoBehaviour

Edited July 30, 2015 by linuxgurugamer