math question.

[Arugela]

Watching this video:

Ran into something familiar playing with stuff on a calculator:

 

2*2*pi*pi = 39.47841760435743447534

 

4*pi*2*2 = 50.2654824574366918154

Spoilers = junk

Spoiler

10.8-10.78706485307925734006 = 0.01293514692074265994

 

39.47841760435743447534/10.78706485307925734006 = 3.65979236632548769448

 

50.2654824574366918154/10.78706485307925734006 = 4.65979236632548769448

 

4.65979236632548769448-3.65979236632548769448=1?!

 

4.65979236632548769448*1.6180339887498948482 = 7.53970242923194004953

 

50.2654824574366918154/7.53970242923194004953 = 6.66677271805237185455

 

39.47841760435743447534/1.6180339887498948482 = 24.39900390155509338309

 

39.47841760435743447534+50.2654824574366918154 = 89.74390006179412629074

50.2654824574366918154/39.47841760435743447534 = 1.27323954473516268615

 

2*2 = 4

 

pi*pi = 9.86960440108935861883

 

4*pi = 12.56637061435917295385

 

Spoiler

ans-9.86960440108935861883 = 2.69676621326981433502

 

12.56637061435917295385/9.86960440108935861883 = 1.27323954473516268615

 

1.27323954473516268615*pi = 4

 

I'm used to this: (fundamentally derived from a cube. Or an equilateral triangle?)

1.5^1*1.3...^1 = 2

1.5^2*1.3...^2 = 4 = 2.25 * 1.777...

1.5^3*1.3...^3 = 8 = 3.375 * 2.370...

 

In case it's not obvious:(And I'm not completely sure what this comes too.) When you stair step between values of 2 you use this for volume etc. 288x2=576. 288x1.5 = 432. 432x1.333... = 576. 2x2 = 4. 2x1.5=3. 3x1.333... = 4. 2/3/4 triangle stepping. This is also related to equilateral triangles as they are double a 234 triangle. And 234 triangles are 1/4th of a sqaure and 1/6th 1/12th of a hexagon if I'm not mistaken.

 

Then I realized: (Is this the circle version somehow?!)

1.27323954473516268615*pi = 4 = sqrt(1.27323954473516268615)^2*sqrt(pi)^2 = 1.1283791670955125739^1*1.7724538 = 2

So:

1.1283791670955125739^1*1.7724538509055160273^1 = 2.000000000000000000

1.1283791670955125739^2*1.7724538509055160273^2 = 4.000000000000000000 = 1.27323954473516268616 * 3.14159265358979323847

1.1283791670955125739^3*1.7724538509055160273^3 = 8.000000000000000000 = 1.43669697700133249353 * 5.5683279968317078453

 

 

 

What are these called? They are different ways to derived dimensional change from a shape. IE linear 2d and 3d changes. 2 is linear, 4 is a square, 8 is a cube.

 

BTW, those slices of partial circles are calculatable/identifiable if you do stuff with sacred geometry and euclids elements.(not sure off hand) They are probably definable proportionally also. But they represent the difference between those two formulas. pi^2 * r^2 and 4pi *r^2

 

Should pi be looked at as a 2 dimensional value? And it's root a 1 dimensional value? and sqrt(pi)^3 = 5.56832799683170784528 as three dimensional?

 

Also notice the similarities of the value 1.7724538509055160273 to 1.777... I think it is some pivot point between the difference between the two variations of the formula. Is pie related to the difference fundamentally?

 

This is derived from the 2/4 in the formula. But is this some alternative to the values in scaling of 2d and 3d shapes. Does this work for circles/spheres specifically somehow?

 

Edit: To boot those curves if derived from a circle usually represent the length of 1 or the radius of a circle. Not sure how it translates into 3d from 2d. (ignore the outside patterns. They are not perfect because of how the program draws circles.)

Edited January 19 by Arugela

[Shpaget]

13 hours ago, Arugela said:

pi*pi = 9.86960440108935861883

4*pi = 12.56637061435917295385

12.56637061435917295385/9.86960440108935861883 = 1.27323954473516268615

 

1.27323954473516268615*pi = 4

Does this surprise you? Were you expecting something else? Are you confusing yourself by writing out all those decimals?

This is equivalent to (4*(pi^2))/(pi^2). Square pies cancel out and you are left with 4.

13 hours ago, Arugela said:

Should pi be looked at as a 2 dimensional value?

I wouldn't.

[StrandedonEarth]

Going off on a geometrical tangent here, but back in the 80's I saw a comic captioned "Pythagoras trips over the hypotenuse" showing an ancient Greek tripping over a broomstick leaning against a wall (obviously at a fairly low angle). Google does not appear to have ay record of it, and I don't even remember the name/author of the comic, or even if it was a regular strip. Perhaps one of our more artistically inclined forum-goers here could recreate it?