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My number is bigger than yours! 3


Guest alemagno12

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Take Graham's Number. It is defined as:

3ÃŽÃŽÃŽÃŽ3 = G1

\ /

3ÃŽÃŽÃŽÃŽÃŽÃŽÃŽ <-- G1 ÃŽs --> ÃŽÃŽÃŽÃŽÃŽ3 = G2

And so on until G64, which is Graham's Number.

This number is tiny.

Continue this until GG (ie G(Graham's Number)).

Replace all 3s with GGs. The number of arrows in the first line is now GG as well. Hence:

GGÃŽÃŽÃŽÃŽ <-- GG ÃŽs --> ÃŽÃŽÃŽÃŽGG = GG1

But,

GG2 = GG1ÃŽÃŽÃŽÃŽ <-- GG ÃŽs --> ÃŽÃŽÃŽÃŽGG1

Repeat until GGG.

Now, GGG1 = GGGÃŽÃŽÃŽÃŽ <-- GGG ÃŽs --> ÃŽÃŽÃŽÃŽGGG, and so on.

Repeat until GGGGG <-- GGGGG <-- GGGGG <-- ... <-- G Gs --> ... --> GGGGG --> GGGGG --> GGGGG

With G64 (Graham's Number) number of pairs of arrows.

That is my number. I call it Sunjumper's Mediocre Number.

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Guest alemagno12

Ok.

Let define GG1 = GG^(GG)^GG where a^(n)^b = a^^^...^^^b with n arrows

Let define GG2 = GG1^(GG1)^GG1

Let define GGn = GG(n-1)^(GG(n-1))^GG(n-1)

Let define GGG1 = GGG^(GGG)^GGG

Let define GGG2 = GGG1^(GGG1)^GGG1

Let define GGGn = GGG(n-1)^(GGG(n-1))^GGG(n-1)

Let define GGG...GGG1 = GGG...GGG^(GGG...GGG)^GGG...GGG

Let define GGG...GGGn = GGG...GGG(n-1)^(GGG...GGG(n-1))^GGG...GGG(n-1)

Let define H1 = GGG64, and Hn = GGG...GGG64 with H(n-1) G's

Let define HG1 = HG^(HG)^HG

Let define HGn = HG(n-1)^(HG(n-1))^HG(n-1)

Let define HGGG...GGG1 = HGGG...GGG^(HGGG...GGG)^HGGG...GGG and HGGG...GGGn = HGGG...GGG(n-1)^(HGGG...GGG(n-1))^HGGG...GGG(n-1)

Let define HH1 = HGGG64 and HHn = HGGG...GGG64 with HH(n-1) G's

Number is HH64

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Guest alemagno12
25,000,000,000(c 300 ) x300

c=the speed of light

Answer: A REALLY BIG NUMBER which no online calculator can get.

I have an even bigger "number"...

​∞

122612_mp_2_principal.jpg

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SYSTEM OVERLOAD

RESTART due to violation of rule 3 (more than 10 number digits for calculation).


[COLOR=#800080]public[/COLOR] class HN {
[COLOR=#800080]private static final double[/COLOR] [COLOR=#0000ff]number[/COLOR] = 15;
[COLOR=#800080]private static final double[/COLOR] [COLOR=#0000ff]exponent[/COLOR] = 250;

[COLOR=#800080]public static void[/COLOR] main (String[] [COLOR=#ff8c00]args[/COLOR]) {
[COLOR="#800080"]double[/COLOR] [COLOR=#ff8c00]answer[/COLOR] = Math.[I]pow[/I]([COLOR="#0000FF"]number[/COLOR], [COLOR="#0000FF"]exponent[/COLOR]);
System.[I][B][COLOR=#0000ff]out[/COLOR][/B][/I].println([COLOR=#ff8c00]double[/COLOR]);
}
}

I call this the HN function. I'll be reusing it for the time being.

BTW this class (as it is called in Java) calculates 15^250, and returns 1.054e+294 (well within the limits of Java doubles). Also in case you are wondering, it does not violates rule 3c or 8 (I think).

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