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AHHans

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    Senior Antenna Wrangler
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    Bonn, Germany

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  1. It can help keeping your Kerbals from running into spinning fan blades. Some may also think that they look nice.
  2. Well, that's at least what some German party-pooping politicians said.
  3. Not that I know of. But I'm sure they had CEOs that ran the company like their own private fiefdom. And, yes, the company deals with nuclear fuel. (I'm sure, if you asked them nicely they could help you to some weapons-grade U235.) Although the company is mostly (in-)famous for they way they(*) ... errr ... mislaid some few thousand (cough) barrles of nuclear waste in the late 1980ies. (*) Technically one of their daughter companies: Transnuklear.
  4. Which used to be a subsidiary of Nukem GmbH, which also owned Nukem Corp. in the USA.
  5. As @king of nowhere wrote: monopropellant ignores crossfeed rules, so it can be transferred from anywhere to anywhere. (And all your RCS thrusters get fuel while you still have monopropellant!) Also, heat shields block crossfeed and cannot be "unblocked" like decouplers. There are only two options: put fuel ducts across the heat shield(s) (in both directions in order to allow fuel transfer!) or disable the "Resurce Transfer Obeys Crossfeed Rules" options in the advanced difficulty settings. And a bonus piece of trivia: fuel that is freshly created from ore will ignore all crossfeed rules and just gets deposited in the tank with the highest priority that is available.
  6. Have a look at the relevant wiki page: Probe Control Point On the controlling ship you always need a relay-type antenna, i.e. either the HG-5, or one of the RA-... antennas. And when using the Mk2 lander can then you need at least two pilots on the ship. If you are close enough then you can indeed use only the internal antenna on the controlled probe. P.S. I actually have never used that feature myself: I always found it easier to build a relay network that gives a connection back to the KSC.
  7. The following popped up in my youtube suggestions. It's the communication between Huston (and/or SpaceX) and the ISS during the recent event when the ISS crew had to shelter from the debris cloud:
  8. Thanks! I knew you could explain that better than me. Picture me adding a number of "That's exactly what I meant" to your post. Well, looking at what I wrote, I didn't explain that well. You used the total gravitational force of the Moon in your calculations. But the gravitational force of the Moon mostly keeps Earth in its orbit around the barycenter. Only the difference between the Moon's force at the position on the Earth's surface and of the Moon's force at the Earth's center of gravity actually matters. From the Wikipedia article: Black circle: Earth. The Moon is far to the right. The top picture shows the Moon's gravitational force on the surface away from the Moon, in the center, and on the surface facing the Moon. The lower picture shows the residual forces after the force at the center is subtracted. (Well, with the actual difference exaggerated for effect.) This residual force is called tidal force, and is the only one that will change the direction of "down" due to the Moon being at a different position relative to you. (Which is how it causes the actual tides.) In reality the Earth's surface will also deform somewhat with the tides and lower their effect on you as you stand on the Earth's surface, but I just ignored that in my calculation. So, you want to prevent - or at least mitigate - something like what happened here: https://www.youtube.com/watch?v=ph9O9yJoeZY
  9. Try to expand our current understanding of physics! E.g. figure out if the relation between its inertial and gravitational mass is the same as for regular matter. But after I ran out of ideas for that, I'd probably use it to convince the funding agencies to keep funding me for "safekeeping" of the antimatter.
  10. [P.S. I'm a bit late to the party, but now I already typed it, so you can damn well take the time and read it! (Or just ignore it, whatever.)] I don't think so. The Earth-Moon barycenter is about 75% of the Earth's radius away from the Earth's center. That means that as the Earth rotates the direction from any point on the surface to the barycenter changes by tens of degrees each day. I guess we would have noticed if that was also how the gravitation changes. The thing is we are not in an orbit around the Earth-Moon barycenter, but more ore less stationary on the Earth's surface. Which is in a complex motion around the barycenter. So I guess what matter in the end is the tidal force that the Moon effects on the Earth's surface. According to the Wikipedia article the corresponding acceleration is: gtidal = 1.10×10−6 m⋅s−2 Compare to Earth's gravity: gtidal / gEarth = 1.10×10−6 / 9.81 =1.121×10−7 Which corresponds to a maximum angle of about 0.02 arcsec This ignores all the more Earthly effects to the local gravity, like the mountain range over there, or variation in density of the Earth's crust (and mantle?), or whatever. If I remember the late night discussions in my student dormitory correctly (back when I still lived in one) then these variations can be quite significant and need to be taken into account by civil engineers. (Which IIRC they do by defining elevation in terms of local gravity.) Your math is fine. But the force actually changes less than the value you used, because you move around relative to the Moon . You can also notice that by the fact that any wheeled craft that you "launch" from the SPH will roll forwards (towards the middle) on the runway. Because the ends of the runway are tilted with regards to the local gravitational field.
  11. I guess you want something like what is reported in issue #22946 on the bug tracker: i.e. that the control actions from SAS (and the built-in trim) can be used as inputs for e.g. a KAL. As you can see, this feature request has been around for a while, but feel free to upvote it on the issue tracker. They are "analog" inputs for the robotics parts. E.g. when you want to move something that shouldn't also be mapped to one of the other axes. And: Welcome to the Forums!
  12. Yes. By setting the semimajor-axis and the eccentricity to the appropriate values. The values in the set-orbit page are the orbital elements of the target orbit, see e.g. the Wikipedia page: https://en.wikipedia.org/wiki/Orbital_elements One initially confusing issue is that the semimajor-axis on the set-orbit page includes the radius of the target body, in contrast to the altitude, AP, PE values given in the game.
  13. Ah, yes. This happens. It is also the supposed behavior. As hinted to above: with the big convert-o-tron and no fuel/oxidizer/monoprop consumption the total mass of the craft should not change. It'll just convert asteroid mass to ore to fuel.
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