Chrisd857

121 = Γ(4)!! + Γ(4)!! + 4! + !(√4)

But I haven't, I swear. 119 = Γ(4)!! + Γ(4)!! + 4! - !(√4)

117 = A( √(!4), √(!4) ) + Γ(4)!! + 4!! Such a post rate!

115 = A( √(!4), √(!4) ) + Γ(4)!! + Γ(4)

113 = A( √(!4), √(!4) ) + Γ(4)!! + 4

111 = A( √(!4), √(!4) ) + Γ(4)!! + √4

109 = A( √(!4), √(!4) ) + Γ(4)!! * !(√4)

So many ninjas. 107 = A( √(!4), √(!4) ) + Γ(4)!! - √4

106 = A( √(!4), √(!4) ) + Γ(4)!! - √(!4)

103 = A( √(!4), 4 ) - 4! + √4 blegh, double ninja'd 105 = A( √(!4), 4 ) - 4! + 4

I've had trouble on !(√4) (it thinks the bang is a NOT symbol) 94 = 4!! * 4!! + 4! + Γ(4)

92 = (4!! + √4) * !4 + √4

One thing I've always wondered is: how to get that smooth changing of camera aimpoint? I now how to move it with the mouse, but I don't off-hand know a nice way to do it.

88 = A( √4, 4 ) * ( 4 + 4 )

No. Again, this is close. I will give another hint: restrict yourself to the category of human technology.

86 = A(√(!4), √(!4)) + 4! + !(√4)

No, but ... closeish.

Well, here goes. It's not quite as poetic as some others, but hopefully it's a good riddle.

I was there a couple years ago, and there were the two upright replicas. I don't recall the Apollo mockup (bottom left), but it might just be my memory. They've got a real Saturn V horizontally in the building, along with a capsule (that re-entered) and a bunch of other stuff.

84 = A(√(!4), √(!4)) + 4! - !(√4) (61) + (24) - 1 I just used the Ackermann function; mind blown yet?

cellulose?

Last I knew, it was a bug in the Unity thermal model. Because the center of the jumbo-64 tank is further away (than smaller tanks), heat is conducted away slower, leading to overheats. IIRC Edit: ninja'd

81 = !4 * !4 + (4-4)

79 = (Γ(4)!) / (!4) - 4 / 4

77 = (Γ(4)!) / (!4) - 4 + !(√4)