rpayne88

1. No 2. 0 3. A vintage 2007 Samsung Juke 4. It mostly replaces a watch for me. 5. Completely disagree. You may want to include some demographic information about the people replying. Age: 18 Gender: Male Race: Caucasian Occupation: Student

Or use high bypass engines. The air is routed around the combustion chamber to cool the engine. I THINK this is how turboshaft engines used in helicopters stay cool.

I agree with you 100%. If you can't even make a valid effort to find a job, why should I be REQUIRED to support you. I'd rather see that money going either to people who actually need it (i.e. laid off with four children) or to some research program. That being said, I predict that this thread will soon be locked.

I've gotten 115 up in one go. No asparagus, with FAR and RT, with zero debris, and no nukes.

Sorry if I'm necroing this thread. I just replaced the router with a SURFboard SBG6580. Now, its dropping out more often. On the up side, though, I can reconnect it from my computer.

First off, I know that KSP is still 32-bit due to limitations with the Unity engine. That is not what I'm posting this about. My question is, why do non-indie developers such as EA, still make games as 32-bit applications. I mean, first I started playing MOH Tier One (the campaign,) encountered lag, quit, started BF3 campaign, hit lag, and quit again. My specs: 8GB RAM 3rd gen Intel i7-3630QM quad core NVIDIA GeForce GT650M 64-bit Windows 7 I can understand Squad because they are an indie developer with a relatively small budget. Yet, multi- million dollar developers making big budget games are still making 32-bit games. We've had 64bit OS for years now, and frankly, if a game needs more than 4gb of memory (otherwise it wouldn't lag in the first place) then why make it a 32bit process?

Same here, and I can't afford a plane ticket down there, and I don't think my flight instructor (my parents are paying for my flying lessons, not me) will sign off on an X/C solo down there.

Saturn V. It is still the only LV capable of launching a manned spacecraft beyond LEO.

Not an issue in binary. To my computer, "2" and "4" don't exist.

I didn't have an experience like yours but I would say the first time I stalled a light plane. Not too dangerous given the fact I was with an instructor at 5000 ASL (probably around 4980 AGL,) but still. One moment, it seems like your straight up with a stall horn going of n your ear, with your airspeed around 40 knots (one knot equals one nautical mile per hour or 1.15 statue miles per hour.) The next, you seem to be straight down with your airspeed shooting past 90 kt (and I was flying a slow Cessna 152. Oh, and Vne, never exceed speed, is 109 kt.)

If you launch in the U.S., you would run into issues with the FAA. They don't need to risk a mid-air collision (you've got a higher chance of getting struck by lightning, surviving, and hitting the lottery in one day) between your rocket (now referred to as a SAM by the FAA) and a plane. An easy solution to this problem: launch it from a boat in international waters and make sure it does not come down anywhere it shouldn't.

Binary for Dummies: 1+1=10 Why? Binary was originally designed for computers (I think.) An electrical circuit can be one of two things: on or off. Either the circuit is complete, or it isn't. To get around the issue of only having two potential outcomes to an input, eight bits (aka a single on/off) were grouped together to form a byte (pronounced as "bite.") Solving this issue relies on exponents of base two (since there can only be two options for an individual bit.) 1 0 0 1 1 0 1 1 2^7 2^6 2^5 2^4 2^3 2^2 2^1 2^0 (I wish I could make true exponents on this forum) so, you get ((2^0)*1)+((2^1)*1)+((2^2)*0)+((2^3)*1)+((2^4)*1)+((2^5)*0)+((2^6)*0)+((2^7)*1) Simplifying a bit (pun intended,) you get (1*1)+(2*1)+(4*0)+(8*1)+(16*1)+(32*0)+(64*0)+(128*1) Taking it farther, you get 1+2+0+8+16+0+0+128 So your final solution is 155. Lets use 1+1=10 as another example. In binary, it looks like 00000010. I'm going to skit the work for the first six zeros (as it would be a headache to type all of them. In decimal, 1+1=2. Now it is a matter of conversion. The figure "2" is not a valid figure in binary. However, we can use binary to arrive at this solution. 1 0 2^1 2^0 So we get: ((2^1)*1)+((2^0)*0) Which equals: (2*1)+(1*0) Which in turn equals: 2+0 Which finally equals 2, however, two is represented as "10" in binary. You can go beyond 2^7; I stopped there because binary is mostly used in computers, and, IIRC, early computers only used eight bits to a byte. Today, however (and someone correct me if I'm wrong) we go up to 2^63 (64 bit processes.) Edit: And for some reason, its not maintaining the spacing for the examples.

Only for NUCLEAR weapons. @Rjhere: Unfortunately (or fortunately depending on your viewpoint,) North Korea can't even feed its own population (causing mass famine.) Its kind of hard to start a war if your population is hunting/ farming for sustenance,

Flying (don't like paying for it, though,) KSP, Gaming, Geocaching, Model Rocketry.

It seems like you've accomplished more in four hours than NASA has in 45 years.

See #5: http://www.tickld.com/x/20-jokes-that-only-intellectuals-will-understand The major difference between "math" and "science/engineering/ksp" is that "math" wants an infinite amount of accuracy. This accuracy leads to stuff like 5sqrt(2) where as engineering would use 7.07106781. I've been in your situation before, though.

May I second that? I can land with no problem. Stopping is another story with KSP's brakes.

Two problems: 1. Funding. This is going to cost millions, if not, billions of USD. That is going to be the hardest problem to solve without serious backing by major companies (Google, Amazon, ect.) 2. Would the various world governments allow you to use the ISS? You are going to have crew at the ISS for more than a month. They may not let you use the ISS's life support for that long. other then that, go for it.

Just throwing this out here. If any of you want to play with realism but forget which light goes where, I came up with the three "R's:" Red, Right, Rong (Yes, I know how to spell "wrong," but you don't pronounce the "w.")

Never mind this post.

I've used one, and I'm only 18. Granted, I've only ever used on once and that was at my grandparent's.

I know Mythbusters tested that in one of their episodes. I don't remember the results, though.

The rocket has a payload bay. The plan is to place the rocket on the pad, turn on the reaction wheel, replace the nose cone, and launch. It will be spooled up by launch and won't even be needed for a few seconds afterwards when the 1st stage burns out. The first few seconds would be stabilized by the fins. The reaction wheel is only needed for the four seconds between 1st stage MECO and 2nd stage ignition. The idea is to keep the rocket pointing straight up during that time. What I want to know is how to calculate the requirements (for lack of a better word) of the reaction wheel.

Its the same in 2013. The only people I can think of that still use it would be the Library of Congress (since they have every form of media ever used.)